How to convert a kotlin source file to a java source file? i must be dense.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above. We use cookies to ensure you have the best browsing experience on our website. We have three such hat puzzles for you in this month’s Insights column. contains further ambiguities; does “allowed only to say ‘Red’ or ‘Blue” mean those are the only words permitted, or the only actions at all? [Read more…] Checkout more Logical Puzzles Tags: Hats Puzzles, Solved Puzzles.

Keep Learning. Answer : A better solution exists for 75% chance of winning. Then if #2 sees a blue hat on #1, his must be red, and if #1 has a red hat, his must be blue. What is the maximum number of correct guesses in this strategy? ), Puzzle 5 | (Finding the Injection for Anesthesia), Puzzle 3 | (Calculate total distance travelled by bee), Puzzle 4 | (Pay an employee using a 7 units gold rod? The next person says that color (and remains alive). now knows whether the remaining number of blue hats, including his own, is odd or even, by taking into account whether #99 had a blue hat or not. Editor’s note: The reader who submits the most interesting, creative or insightful solution (as judged by the columnist) in the comments section will receive a Quanta Magazine T-shirt. ), Puzzle 5 | (Finding the Injection for Anesthesia), Puzzle 3 | (Calculate total distance travelled by bee), Puzzle 4 | (Pay an employee using a 7 units gold rod? Abusive, profane, self-promotional, misleading, incoherent or off-topic comments will be rejected. This strategy wins in all six cases with at least one hat of each color. –> i see 98 hats, even, i must wear the blue one #98: blue! Does freedom of speech mean freedom to mock everything? But there is almost always a clever way to save most of them, or sometimes even all of them, that is quite unexpected and elegant. to “signal” hat colors to one another is simply that this is meant (i assume, since it was proposed by a math professor) to be
other solutions are not wrong, are they? –> i see 0 hats, even, i must wear the red one #98: red! acknowledge that you have read and understood our, GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Puzzle 51| Cheryl’s Birthday Puzzle and Solution, Puzzle 1 | (How to Measure 45 minutes using two identical wires?

DESCRIPTION: Each one can see the hats that are in front of them, and not their own. Why do the brakes "freeze" the suspension? Then the second prisoner, by looking ahead and counting the number of blue hats, knows his must be blue if he sees one blue hat, and red if Finally, the rules make no exclusions The contestants are not permitted to say anything other than a color (blue, red or yellow), and they can speak it only once.

If the number is even, that means the hat on his head is black. By using our site, you Note that we will hold comments for the first day to allow for independent contributions. If this number is even, he (loudly) guesses the hat on his head as ‘Black’. Therefore, our assumption is true. Nowhere does it say that there is an even distribution of red and blue hats among the 100 participants. ), Correct Answer:  Vasu is the Knight, Ram is the Spy and Shyam is the Knave. The third prisoner can see 0,1, or 2 blue hats. What will the final position of the moon be?Read more…, Do markets and morality — as we like to definite fairness in modern societies — reinforce one another?Read more…. Two “blues” or two “reds” in a row mean he wears blue, while one blue and one red means he wears red. As expected, each contestant can see the colors of the hats of everyone in front of her but does not know the color of her own hat or those of anyone behind. Explanation: We know that the knight never lies, knave always lies and spy sometimes lies. Does a gear retain its mechanical advantage in a 1 2 1 ratio? Stack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.